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-16x^2+128x=87
We move all terms to the left:
-16x^2+128x-(87)=0
a = -16; b = 128; c = -87;
Δ = b2-4ac
Δ = 1282-4·(-16)·(-87)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10816}=104$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-104}{2*-16}=\frac{-232}{-32} =7+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+104}{2*-16}=\frac{-24}{-32} =3/4 $
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